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Smart Capacitor power supply

Description

Table of Contents:

  1. Smart Capacitor power supply
  2. Free TI Design & Simulation Tools
Contributor: 
D.Mohankumar

WEBENCH Design Center

WEBENCH Design Environments are unique and powerful software tools that deliver customized power, lighting, filtering, clocking and sensing designs in seconds. These easy-to-use tools help you generate, optimize and simulate designs that conform to your unique specifications. They allow you to make value-based tradeoffs at a design, system and supply chain level before your design is committed to production.



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Comments (5)

Thank you for your valuable

Thank you for your valuable information.

i expect more isolation in this case . that is this is tfr less supply . But why we give a small tfr use here at low cost that is i think input voltage is if less than 100V b/w the capacitor after droping the voltage across the it.

Pls . give me your valuable suggestion .....

 

Shibu AS

Pachalam. Ernakulam

Shibuas@ymail.com

what is the rating of

what is the rating of capacitor ?

also please tell how to convert it to 5 v power supply ?

Hi, the above cap has a value

Hi, the above cap has a value 225. This means (2200000/1000000) ?F or 2.2 ?F. For 5v low current transformerless power supply, simply built a circuit using a 474k x rated cap with voltage rating 400v. Then use a 7805 ic to get a regulated 5v output. I have built a couple of transformerless powersupplies. You can have a look at www.youtube.com/shiharanchoudhury For any queries, doubts please feel free to mail me at shiharanchoudhury@yahoo.in

1.what is a smart

1.what is a smart capacitor? 

what are its applications?

please explain its working?

 

2.Please explain how MOSFET can be used as a switch.

Thank you for you work I have

Thank you for you work

 

I have some issues i will be appriciated if you kindly help with

 

1- What is the Bridge Ractifier output voltage ,is it calculated based on the following equation:

 

Vout = Vpk X 0.637 = Vrms X 1.414 X 0.637 or Vout = Vrms X 0.9 where Vrms = 230/3 = 115 thus

output voltage of the bridge = 115 X 0.9 = 103.5V where you said

 

voltage rating of the smoothing capacitor should be three times higher than that of the rectified voltage. Here 60 volt capacitor is used. Smoothing of DC which mean the ractified voltage = 60/3 = 20V how we get this voltage, I understand that this related to the capacitance property for C1 and C2 how this value calulated.

 

2-how we calculate the value of R3

 

sorry for any inconvinince but i am new in this aspect and i am just a hobbiyst and there is no good information regarding this type of circuits on the web.

 

Regards

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