DC Motor Speed Control using Chopper

In many different applications it is required to control speed of DC motor. Some of the examples are

· In treadmill machine it is required to vary the speed of motor that used to roll the belt

· The speed of DC motor used in railway engines (traction) has to be varied

· E-bikes, e-bicycles, e-scooters also runs on DC motor and to vary their speed it is required to control speed of DC motor

· DC motors are also used in portable sewing machine, drill machine etc, in which speed control of motor is provided for different operation

One of the popular methods of speed control of DC motor is using chopper. Chopper is a device that gives variable DC output from applied fixed DC input. It simply chops fixed DC and generates variable DC. Let us first understand how it generates variable DC.

Block Representation of Chopper circuit used to control rotation of DC Motor

Fig. 1: Block Representation of Chopper circuit used to control rotation of DC Motor

As shown in figure the chopper supplies fixed DC voltage to motor. When chopper is ON motor gets supply but when chopper is off motor does not get the supply. So as shown in figure let us say chopper is on for Ton time and it is off for Toff time. So depending upon the Ton and Toff time the DC voltage applied to motor is

Vdc = [T_on / (T_on + T_off)] × V_fixed

But T_on + T_off = T_total

So Vdc = [T_on / T_total] × V_fixed

Here T_on / T_total is called duty cycle. So as duty cycle is more the average DC voltage supplied to motor is more and so speed of motor is increased. So as duty cycle is varied by varying on and off time of chopper, the speed of motor can be varied.

The given circuit demonstrates one of such chopper circuit using Zero Cross Detector (ZCD), timer IC NE555 and darlington amplifier TIP122 used as chopper device. The circuit chops rectified DC output and varies the speed of DC motor.

Circuit Description

· 230V @ 50 Hz AC is applied at the primary of transformer T1 (0-12 VAC, 500 mA). It’s secondary is connected with AC input terminals of bridge rectifier BR1.

· Rectified output is given to base of transistor Q1 through voltage divider formed by resistors R1 (1K) & R2 (1K).

· Collector output of Q1 is fed to base of transistor Q2 through R4 (470Ω). Q1 and Q2 both are connected in switch configuration as shown.

· The output of Q2 is applied at the trigger input of NE555 chip U1. It is configured in monostable mode. Timing components RV1 (10K pot) and C1 (1 µF) decides width of output pulse

· Output of U1 is applied to base of darlington transistor TIP122 through current limiting resistor R6

· The DC motor is connected between rectified output and collector of TIP122. The emitter of TIP122 is connected to ground

(Check the circuit diagram tab for complete circuit for DC motor speed control using chopper)

Circuit Operation

Let us understand the circuit operation with the help of waveforms at different points A, B, C, D, E and F

Timing Diagram of Signals at various stages of the chopper circuit

Fig. 2: Timing Diagram of Signals at various stages of the chopper circuit

· Step down transformer T1 steps down 230 VAC into 12 VAC as shown as waveform 1 above figure at point A

· This AC input is given to bridge rectifier. Bridge rectifier will produce rectified DC output as shown in second waveform if above figure at point B

· This rectified output is given to base of transistor Q1. Because transistor Q1 is connected in switch configuration, when the input at the base becomes lower than 0.7 V it comes into cutoff and produces very short duration positive pulse at point ‘C’. That is shown as 3^rd waveform in figure

· As this positive pulses are given to Q2 which is again connected in switch configuration, it will produce negative pulse at point ‘D’ of same width of positive pulse. This is shown as 4^th waveform

· These negative pulses are applied to trigger input of NE555 chip connected in monostable mode. So it will generate high output every time when it gets this negative pulse. Its time period can be varied from 0 milisecond to max 10 milisecond using 10 K pot

· As per the waveforms given in below figure let us understand 2 different cases with pulse width of NE555 3 ms and 8 ms

· As shown a second waveform in above figure, the NE555 will generate high output when gets negative pulse at its trigger input. For first case the width of pulse is 3 ms

· Because this pulse is given to base input of TIP122, it is turned ON till pulse is high. When TIP122 is ON the motor gets chopped rectified output as shown in 3^rd waveform in figure. Out of total 10 ms time, the motor gets DC waveform for 3 ms only

· So average voltage applied to DC motor is less (as shown in waveform) and its speed is also less

Timing Diagram of Output Waveforms from the Chopper Circuit

Fig. 3: Timing Diagram of Output Waveforms from the Chopper Circuit

· As shown in 4^th and 5^th waveforms, now the time period (pulse width) of NE555 is increased to 8 ms. So the rectified output applied to DC motor is also more – means average voltage applied to motor is more and its speed is more

· Thus as time period (width of output pulse) of NE555 is varied from 0 ms to 10 ms, it gives chopped rectified DC wave to motor that will vary its speed from min to max.